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NCERT Solutions for Class 8 Maths Exercise 16.2 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free

**NCERT solutions for Class 8 Maths Playing with Numbers Download as PDF**

## NCERT Solutions for Class 8 Maths Playing with Numbers

**Class –VIII Mathematics (Ex. 16.2)**

**NCERT SOLUTION**

**1. If 21***y*^{5} is a multiple of 9, where *y *is a digit, what is the value of *y*?

*y*

^{5}is a multiple of 9, where

*y*is a digit, what is the value of

*y*?

**Ans.** Since 21*y*^{5 }is a multiple of 9.

Therefore according to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.

Since 21*y*^{5} is a multiple of 9.

**2. If 31***z*^{5 }is a multiple of 9, where z is a digit, what is the value of z? You will find that there are *two *answers for the last problem. Why is this so?

*z*

^{5 }is a multiple of 9, where z is a digit, what is the value of z? You will find that there are

*two*answers for the last problem. Why is this so?

**Ans.** Since 31*z*^{5} is a multiple of 9.

Therefore according to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.

If

Hence 0 and 9 are two possible answers.

NCERT Solutions for Class 8 Maths Exercise 16.2

**3. If 24***x *is a multiple of 3, where *x *is a digit, what is the value of *x*?

*x*is a multiple of 3, where

*x*is a digit, what is the value of

*x*?

**(Since 24 x is a multiple of 3, its sum of digits 6 + x is a multiple of 3; so 6 + x is one of these numbers: 0, 3, 6, 9, 12, 15, 18, … .But since x is a digit, it can only be that**

6 + x = 6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of (four different values.)

**Ans.** Since is a multiple of 3.

Therefore according to the divisibility rule of 3, the sum of all the digits should be a multiple of 3.

Since is a digit.

Thus, can have any of four different values.

NCERT Solutions for Class 8 Maths Exercise 16.2

**4. If 31***z*^{5 }is a multiple of 3, where z is a digit, what might be the values of z?

*z*

^{5 }is a multiple of 3, where z is a digit, what might be the values of z?

**Ans.** Since 31*z*^{5} is a multiple of 3.

Therefore according to the divisibility rule of 3, the sum of all the digits should be a multiple of 3.

Since is a digit.

If

If

If

Hence 0, 3, 6 and 9 are four possible answers.

## NCERT Solutions for Class 8 Maths Exercise 16.2

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